12x^2-104x-105=0

Solution for 12x^2-104x-105=0 equation:

12x^2-104x-105=0

a = 12; b = -104; c = -105;
Δ = b2-4ac
Δ = -1042-4·12·(-105)
Δ = 15856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15856}=\sqrt{16*991}=\sqrt{16}*\sqrt{991}=4\sqrt{991}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{991}}{2*12}=\frac{104-4\sqrt{991}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{991}}{2*12}=\frac{104+4\sqrt{991}}{24}
$